40x^2-12x+1=0

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Solution for 40x^2-12x+1=0 equation:


Simplifying
40x2 + -12x + 1 = 0

Reorder the terms:
1 + -12x + 40x2 = 0

Solving
1 + -12x + 40x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
40 the coefficient of the squared term: 

Divide each side by '40'.
0.025 + -0.3x + x2 = 0

Move the constant term to the right:

Add '-0.025' to each side of the equation.
0.025 + -0.3x + -0.025 + x2 = 0 + -0.025

Reorder the terms:
0.025 + -0.025 + -0.3x + x2 = 0 + -0.025

Combine like terms: 0.025 + -0.025 = 0.000
0.000 + -0.3x + x2 = 0 + -0.025
-0.3x + x2 = 0 + -0.025

Combine like terms: 0 + -0.025 = -0.025
-0.3x + x2 = -0.025

The x term is -0.3x.  Take half its coefficient (-0.15).
Square it (0.0225) and add it to both sides.

Add '0.0225' to each side of the equation.
-0.3x + 0.0225 + x2 = -0.025 + 0.0225

Reorder the terms:
0.0225 + -0.3x + x2 = -0.025 + 0.0225

Combine like terms: -0.025 + 0.0225 = -0.0025
0.0225 + -0.3x + x2 = -0.0025

Factor a perfect square on the left side:
(x + -0.15)(x + -0.15) = -0.0025

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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